K Kurchi New member Joined Sep 4, 2020 Messages 10 Oct 5, 2020 #1 In Sn , order of every element is a divisor of n! . But, is every divisor of n! a possible order for elements of Sn ?
In Sn , order of every element is a divisor of n! . But, is every divisor of n! a possible order for elements of Sn ?
Steven G Elite Member Joined Dec 30, 2014 Messages 14,603 Oct 5, 2020 #2 Yes, of course every divisor of n! is a possible order for elements of Sn. Are you sure that you meant to write what you wrote? Did you meant to ask if every divisor of n! has an element of that order?
Yes, of course every divisor of n! is a possible order for elements of Sn. Are you sure that you meant to write what you wrote? Did you meant to ask if every divisor of n! has an element of that order?
