Systemic Nth roots of a number

pka

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There are six sixth roots of 12+5i\displaystyle -12+5i see here.
12514 See that there are six of them. Each of them is on a circle centered at the origin of radius 12+5i1/6=136\displaystyle |-12+5i|^{1/6}=\large\sqrt[6]{13}
However, the salient feature is the fact the the are evenly spaced on the circle and the central angle between any to adjacent is 2π6=π3\displaystyle \frac{2\pi}{6}=\frac{\pi}{3}. see here
Here is a step by step outline: If N>1\displaystyle N>1 is a positive integer and z=x+yi\displaystyle z=x+yi is a complex number in which xy0\displaystyle x\cdot y\ne 0 (if that case fails there are special considerations).
Because all of this necessitates z\displaystyle z being in polar form, I digress into this:
\(\displaystyle \arg(z)=\arg(x + yi) = \left\{ {\begin{array}{{rl}} {\arctan \left( {\dfrac{y}{x}} \right),}&{x > 0} \\ {\arctan \left( {\dfrac{y}{x}} \right) + \pi ,}&{x < 0\;\& \;y > 0} \\ {\arctan \left( {\dfrac{y}{x}} \right) - \pi ,}&{x < 0\;\& \;y < 0} \end{array}} \right. \) _______keep in mind that \(\displaystyle x\cdot y\ne 0 \text{ implies }x\ne 0~\&~y\ne 0\).

Return to the job at hand. If \(\displaystyle z=|z|\exp(\theta i)\) where \(\displaystyle \theta=\arg(z)\)
Define \(\displaystyle \zeta={\large\sqrt[N]{|z|}}\exp\left(\frac{\theta i}{N}\right)\) _____Do you see that \(\displaystyle \zeta^N=z~?\) I certainly hope you do !
Now we need a "rotator " to distribute the roots of \(\displaystyle z\) equality spaced around a circle. \(\displaystyle \rho=\exp\left(\frac{2\pi i}{N}\right)\)
The set \(\displaystyle \left\{\zeta\cdot\rho^k|k=0,1,\cdots N-1 \right\}\) is the collection of the \(\displaystyle N^{th}\) roots of \(\displaystyle z\).

Here is a practice question: List the seven seventh roots of \(\displaystyle -6-8i\).
 
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