H hrr379 New member Joined Jun 9, 2012 Messages 17 Jun 14, 2012 #1 If there is no sec in the given integral how could you calculate it? For example.... Attachments photo.jpg 79.6 KB · Views: 5
D Deleted member 4993 Guest Jun 14, 2012 #2 hrr379 said: If there is no sec in the given integral how could you calculate it? For example.... Click to expand... tan4(t) = [sec2(t) - 1]2 However, you had the right idea in this case. \(\displaystyle \int tan^4(t) dt \ = \ \int tan^2(t)[sec^2(t) - 1] dt \ = \ \int tan^2(t)*sec^2(t) dt - \int [sec^2(t) -1] dt \ = \ \frac{1}{3}tan^3(t) - tan(t) + t + C \)
hrr379 said: If there is no sec in the given integral how could you calculate it? For example.... Click to expand... tan4(t) = [sec2(t) - 1]2 However, you had the right idea in this case. \(\displaystyle \int tan^4(t) dt \ = \ \int tan^2(t)[sec^2(t) - 1] dt \ = \ \int tan^2(t)*sec^2(t) dt - \int [sec^2(t) -1] dt \ = \ \frac{1}{3}tan^3(t) - tan(t) + t + C \)
