You were asked to use - Taylor's series expansion. For that use:It should be +. I got confused. Anyway how do I reach a solution using the method I tried?
ln(1+a) = a - (a^2)/2 + (a^3)/3 - (a^4)/4 ..... at a = ~0How do I reach the summation formula if I use the Taylor Series expansion? I have no problem figuring out the domain. I am having trouble reaching one of the solutions in the multiple choice.
I know the first one is the correct answerWhich one have you chosen? (Or which ones have you narrowed down to?)
continuing....ln(1+a) = a - (a^2)/2 + (a^3)/3 - (a^4)/4 ..... at a = ~0
ln(1- a) = -a - (a^2)/2 - (a^3)/3 - (a^4)/4 ..... at a = ~0
ln(1+a) - ln(1-a) = 2* [a + (a^3)/3 + (a^5)/5 + a^7)/7 ...]