The Division Logarithm URGENT

[scarlett_B]

I need help!!!! The problem is c(cubed)+4c(squared)-c-4/c(squared)+3c-4


Can someone please help me ASAP

 

[galactus]

You have no grouping symbols.

Here is what you have written:

\(\displaystyle c^{3}+4c^{2}-c-\frac{4}{c^{2}}+3c-4\)

I assume you mean:

\(\displaystyle \frac{c^{3}+4c^{2}-c-4}{c^{2}+3c-4}\)

It's just like regular division. Do it the same way.

I'm sorry, but it is difficult to get this to line up correctly.

Well, you can line up the powers under one another.

               c             +1  
             -----------------------
c^2+3c-4 )   c^3 + 4c^2 - c - 4
             c^3 + 3c^2 - 4c
             --------------------------
                c^2 + 3c - 4
                c^2 + 3c -4
                ----------------------------
                           0

\(\displaystyle c+1\)