S SILVER New member Joined Jan 27, 2011 Messages 18 Mar 11, 2011 #1 how do I solve this problem? Is it a problem with 2 unknowns? or just a normal equation? At the infirmary, four aspirin and five bandages cost a total of $49. Four aspirin and eight bandages cost $64. How much does an aspirin cost?

how do I solve this problem? Is it a problem with 2 unknowns? or just a normal equation? At the infirmary, four aspirin and five bandages cost a total of $49. Four aspirin and eight bandages cost $64. How much does an aspirin cost?

M masters Full Member Joined Mar 30, 2007 Messages 378 Mar 11, 2011 #2 SILVER said: how do I solve this problem? Is it a problem with 2 unknowns? or just a normal equation? At the infirmary, four aspirin and five bandages cost a total of $49. Four aspirin and eight bandages cost $64. How much does an aspirin cost? Click to expand... Hi Yo Silver, It will be a system of 2 linear equations. Let a = cost of aspirin Let b = cost of bandage [1] \(\displaystyle 4a\:+\:5b\:=\:49\) [2] \(\displaystyle 4a\:+\:8b\:=\:64\) Subtract the two equations: [3] \(\displaystyle -3b\:=\:-15\) [3] \(\displaystyle \boxed{b\:=\:\$\:5.00}\) Substitute this answer into [1] or [2] to find a.

SILVER said: how do I solve this problem? Is it a problem with 2 unknowns? or just a normal equation? At the infirmary, four aspirin and five bandages cost a total of $49. Four aspirin and eight bandages cost $64. How much does an aspirin cost? Click to expand... Hi Yo Silver, It will be a system of 2 linear equations. Let a = cost of aspirin Let b = cost of bandage [1] \(\displaystyle 4a\:+\:5b\:=\:49\) [2] \(\displaystyle 4a\:+\:8b\:=\:64\) Subtract the two equations: [3] \(\displaystyle -3b\:=\:-15\) [3] \(\displaystyle \boxed{b\:=\:\$\:5.00}\) Substitute this answer into [1] or [2] to find a.