The square root of 3b-2 minus the square root of 2b + 5 = 1 thank you.
J Jodene222 Junior Member Joined Aug 1, 2007 Messages 51 Oct 27, 2007 #1 The square root of 3b-2 minus the square root of 2b + 5 = 1 thank you.
J Jodene222 Junior Member Joined Aug 1, 2007 Messages 51 Oct 27, 2007 #2 just figured out my own answer just figured out my own answer thanks
stapel Super Moderator Staff member Joined Feb 4, 2004 Messages 16,582 Oct 27, 2007 #4 Jodene222 said: The square root of 3b-2 minus the square root of 2b + 5 = 1 Click to expand... Does the above mean the following? . . . . .sqrt[3b - 2] - sqrt[2b + 5] = 1 Were the instructions to "solve"? Thank you! Eliz.
Jodene222 said: The square root of 3b-2 minus the square root of 2b + 5 = 1 Click to expand... Does the above mean the following? . . . . .sqrt[3b - 2] - sqrt[2b + 5] = 1 Were the instructions to "solve"? Thank you! Eliz.
J Jodene222 Junior Member Joined Aug 1, 2007 Messages 51 Oct 27, 2007 #5 yes, first step moved sqrt [2b + 5] to the other side: .sqrt[3b - 2] = 1- sqrt[2b + 5] then i squared everything: 3b - 2 = 2b + 5 + 2 sqrt[2b+5] + 1 Simplify: b-8 = 2 sqrt[2b + 5] square everything: b^2 - 24b + 44 = 0 (b-2)(b-22) = 0 check {22}
yes, first step moved sqrt [2b + 5] to the other side: .sqrt[3b - 2] = 1- sqrt[2b + 5] then i squared everything: 3b - 2 = 2b + 5 + 2 sqrt[2b+5] + 1 Simplify: b-8 = 2 sqrt[2b + 5] square everything: b^2 - 24b + 44 = 0 (b-2)(b-22) = 0 check {22}
G galactus Super Moderator Staff member Joined Sep 28, 2005 Messages 7,216 Oct 27, 2007 #6 You got it.