Princezz3286
Junior Member
- Joined
- Nov 12, 2005
- Messages
- 66
These questions are more for verification purposes..... I did the problems but I want to make sure I have the right processes
1) 1/3 t - 7 > 2 or 4 - t > 6 (SOLVE EACH EQUATION AND WRITE THE ANSWER IN INTERVAL NOTAITON)
to start I added 7 to the first equation and subtracted 4 from the 2nd equation....
1/3 t > 9 OR - t > 2
then I took the first one and multiplied by the recip. and multiplied the 2nd one by -1
(3/1) 1/3 t > 9 (3/1) OR t > -2 (my question on the 2nd problem is do I flip the sign when multiplying by a - # or is that only for division?)
t > 27 U t < -2 or would it be (t > -2)
{- inf. , -2} U {27 , inf.}
I hope this makes sense.....
2) 4/(c-5) + (c+1)/2c (PERFORM OPERATIONS ANS SIMPLIFY)
FIND THE COMMON DENOMENATOR 2c(c - 5)
8c/2c(c-5) + c^2 - 4c -5/2c(c-5) combine like terms....
c^2 + 4c - 5/ 2c(c-5) then factor the top part of the fraction to get.....
(c + 5)(c - 1)/2c(c - 5) and you can't cancel anything so we are done?
3) this is a double fraction so I will type it the best I can.....the directions are to simplify
(2/ (x - 9)) -1 over 1 + (5/ (x - 9))
I FOUND THE LCD TO BE (x - 9) so I ended up with
((2/x - 9) - ((x - 9)/(x - 9)) all over ((x - 9)/(x - 9)) + (5/(x - 9)) COMBINE LIKE TERMS AND I GOT.....
((x - 7)/(x - 9)) over ((x - 4)/(x - 9)) NOW THIS IS WHERE I GET CONFUSED CAN YOU PLEASE ASSIST FROM HERE IF ALL THE PRECEDING INFO IS CORRECT.
4) (3w / 2w - 1) -6 = (4 / 2w - 1)
- (3w / 2w - 1)
so....
(2w - 1) - 6 = -3w + 4/2w - 1 (2w - 1)
MULTIPLY BOTH SIDES BY (2w - 1)
12w + 6 = -3w + 4
+3w +3w
---------------------------
15w + 6 = 4
-6 -6
------------------------
15w = -2
divide by 15 and get w = -2/15 right?
THANK YOU!
Heather
1) 1/3 t - 7 > 2 or 4 - t > 6 (SOLVE EACH EQUATION AND WRITE THE ANSWER IN INTERVAL NOTAITON)
to start I added 7 to the first equation and subtracted 4 from the 2nd equation....
1/3 t > 9 OR - t > 2
then I took the first one and multiplied by the recip. and multiplied the 2nd one by -1
(3/1) 1/3 t > 9 (3/1) OR t > -2 (my question on the 2nd problem is do I flip the sign when multiplying by a - # or is that only for division?)
t > 27 U t < -2 or would it be (t > -2)
{- inf. , -2} U {27 , inf.}
I hope this makes sense.....
2) 4/(c-5) + (c+1)/2c (PERFORM OPERATIONS ANS SIMPLIFY)
FIND THE COMMON DENOMENATOR 2c(c - 5)
8c/2c(c-5) + c^2 - 4c -5/2c(c-5) combine like terms....
c^2 + 4c - 5/ 2c(c-5) then factor the top part of the fraction to get.....
(c + 5)(c - 1)/2c(c - 5) and you can't cancel anything so we are done?
3) this is a double fraction so I will type it the best I can.....the directions are to simplify
(2/ (x - 9)) -1 over 1 + (5/ (x - 9))
I FOUND THE LCD TO BE (x - 9) so I ended up with
((2/x - 9) - ((x - 9)/(x - 9)) all over ((x - 9)/(x - 9)) + (5/(x - 9)) COMBINE LIKE TERMS AND I GOT.....
((x - 7)/(x - 9)) over ((x - 4)/(x - 9)) NOW THIS IS WHERE I GET CONFUSED CAN YOU PLEASE ASSIST FROM HERE IF ALL THE PRECEDING INFO IS CORRECT.
4) (3w / 2w - 1) -6 = (4 / 2w - 1)
- (3w / 2w - 1)
so....
(2w - 1) - 6 = -3w + 4/2w - 1 (2w - 1)
MULTIPLY BOTH SIDES BY (2w - 1)
12w + 6 = -3w + 4
+3w +3w
---------------------------
15w + 6 = 4
-6 -6
------------------------
15w = -2
divide by 15 and get w = -2/15 right?
THANK YOU!
Heather