Three cousins, product of their ages is 84. Next year the youngest will be 1/4 the age of the middle cousin. In 2 years the oldest will be twice the current age of the middle cousin. What is the age of the oldest cousin?
A < B < C
A+1= 1/4(B+1) so B=4(A+1)-1
C+2=2B so C = 2B-2 = 2(4(A+1)-1)-2
ABC=84
A*(4A+3)*(2(4(A+1)-1)-2) = 84
Solve for A
Hint: A is a positive integer smaller than 84^(1/3) so trial and error is easiest.
This site uses cookies to help personalise content, tailor your experience and to keep you logged in if you register.
By continuing to use this site, you are consenting to our use of cookies.