Is that the same as \(\displaystyle B^D\) ?B^D (4 words)
The rebussy ought to show than one power, according to the powers that be.T-- p----- t--- b-
"the powers that be" - I don't get it! Please explain!The rebussy ought to show than one power, according to the powers that be.
Don't like it!B^D = be(B) to the power the(D) : so the(D) powers that be(B)
Much better!!͏ \(\displaystyle \quad\) ͏
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͏THE
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...which makes it a "rebus puzzle"!I don't see a complete sense. I see a big stretch.