G Guest Guest Apr 7, 2006 #1 I am suppose to translate into an equation and then solve this equation.... The square of a number minus twice the number is 48. Find the number. Let x=the number The equation for this is x^2-2x=48 Then it becomes x^2-2x-48=0 What do I do after this?!? I got lost here....

I am suppose to translate into an equation and then solve this equation.... The square of a number minus twice the number is 48. Find the number. Let x=the number The equation for this is x^2-2x=48 Then it becomes x^2-2x-48=0 What do I do after this?!? I got lost here....

T TanyaGrape New member Joined Feb 9, 2006 Messages 13 Apr 7, 2006 #2 x^2-(2)=48 does that make any sense? ?

G Guest Guest Apr 7, 2006 #3 Oh ok so the 2nd step that I posted isnt neccessary?!?(The step after x^2-2x=48)