Hello,
I'm trying to solve this problem but I have no idea how to continue my solution in order to reach the end. I know what I need to prove but I don't know how. please help
Point F belongs to side BC in the triangle ABC such that AC=BF. Prove that the line starting from the median of CF and parallel to L <)ACB intersects with the median of AB.
My solution (NOT FULL):
Let M be the median of CF, M1 be the median of AB and CL be the bisector of <)ACB. Let E be the median of AF. Therefore triangle M1ME is an isosceles triangle (EM and EM1 are middle segments of AC and BF and AC=BF). I somehow need to prove that <)MEM1=0,5*<)ACB so that CL and MM1 will be parallel.
Please show me how to do so. Thanks in advance : -)
I'm trying to solve this problem but I have no idea how to continue my solution in order to reach the end. I know what I need to prove but I don't know how. please help
Point F belongs to side BC in the triangle ABC such that AC=BF. Prove that the line starting from the median of CF and parallel to L <)ACB intersects with the median of AB.
My solution (NOT FULL):
Let M be the median of CF, M1 be the median of AB and CL be the bisector of <)ACB. Let E be the median of AF. Therefore triangle M1ME is an isosceles triangle (EM and EM1 are middle segments of AC and BF and AC=BF). I somehow need to prove that <)MEM1=0,5*<)ACB so that CL and MM1 will be parallel.
Please show me how to do so. Thanks in advance : -)