Ok, so I saw this problem today and I am completely confused. Triangle with Vertices A. B. C. The triangle is split or disected to form 90 degree angles at the base. This of course now forms two triangles. The one on the left is a 30-60-90 triangle. With vertices mentioned above A=60, B= 30. On the right side of the 30 degree andle where it has been cut in two is an angle of 45 degrees. so I have a 90-45-45 triangle. The Height of the triangle is sqrt of 6. Placeing the letter D where the disecting line is perpendicular to CA.
The question is what is the side lengths of AB, BC, CD, DA
Just curious.[sup:1967dwhr][/sup:1967dwhr]
The question is what is the side lengths of AB, BC, CD, DA
Just curious.[sup:1967dwhr][/sup:1967dwhr]