Trig between 0 and 360: Find beta if tan beta=-5.67 and cos beta <0.

UK123

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Can anyone help with this please, and explain the method? I'd very much appreciate it. Thanks in advance:

In this question, the angle is in the interval 0-360 degrees Answers to 1 dp.

Find beta if tan beta=-5.67 and cos beta <0.
 
Well, what do you know? Do you have a calculator that does inverse trig functions? Do you know how to use it? If so, enter -5.67 into your calculator and press the "\(\displaystyle tan^{-1}\)" key (be sure you are in "degree mode"). That will give the "principal value" which, for arctan, is between -90 and 90. Do you know that "tan" is "sin/cos"? Since this tangent is negative and we are told that cosine is negative sine must be positive. Sine is positive and Cosine negative in the second quadrant.
 
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