trig: C = 66° 34', a = 407, b = 513

[Trig chick]

trig: C = 66° 34', a = 407, b = 513

I need help with the next step in this problem.
C=66 degrees 34'
a=407
b=513

a=407
b=513
a+b=920
a-b=-106
1/2(A+B)=1/2(180 degrees-66 degrees 34')
=56 degrees 43'
tan1/2(A-B)= -106tan56degrees43'
920
log-106=2.02531
logtan56 degrees43'=10.77058-10
12.79589-10
log920 2.96379
logtan1/2(A-B)=9.83210-10
1/2(A-B)= :?:
1/2(A+B)= :?:

 

[Denis]

What is your QUESTION?
Is this about a triangle ABC with BC=407, AC=513 and angle ACB = 66 34' ?
Please type the WHOLE original problem.

And what's a "trig chick"? A hen that lays triangular eggs? :shock:

 

[galactus]

Is this something like the triangle you mean?:

If so, try the law of cosines: \(\displaystyle \L\\c=\sqrt{a^{2}+b^{2}-2(a)(c)cos(C)}\)

That'll get you side c.

 

[stapel]

And what's a "trig chick"? A hen that lays triangular eggs?

Ouch! :wink: :lol:

Note to "Trig chick": Your attempts at multi-line and space-dependent formatting did not succeed. Please either use the "code" tags to force the formatting to be fixed-width and use "preview" (probably multiple times) to get the formatting the way you want, or else use standard single-line formatting and grouping symbols (and words) to make your meaning clear. Or else learn and use LaTeX.

Thank you.

Eliz.