I need to solve this equation
cos ø sin2 ø - sin ^3 ø = 0, find ø if 0< ø < 90°
The exponent 3 has me confused. I know I can substitue 2sinøcosø for the sin2ø then I'll have
cosø 2sinøcosø but I'm lost as to what to do with the sin^3ø.
I'm learning from home and my text doesn't do a good job of explaining.
cos ø sin2 ø - sin ^3 ø = 0, find ø if 0< ø < 90°
The exponent 3 has me confused. I know I can substitue 2sinøcosø for the sin2ø then I'll have
cosø 2sinøcosø but I'm lost as to what to do with the sin^3ø.
I'm learning from home and my text doesn't do a good job of explaining.