i need help with this equation: 2cot2x+cot^2x=1
i know that cot=cos/sin so i think its supposed to be like this 2(cos2x/sin2x)+cos2x/sin2x=1
Im not sure about the last one since its cot^2x
i get stuck and dont know how to proceed, i dont know a lot about cot and how to use it, i tried to read some articles but it dosent help me much, i would be really thankful if someone could guide me through this or try to explain for me. thanks.
i know that cot=cos/sin so i think its supposed to be like this 2(cos2x/sin2x)+cos2x/sin2x=1
Im not sure about the last one since its cot^2x
i get stuck and dont know how to proceed, i dont know a lot about cot and how to use it, i tried to read some articles but it dosent help me much, i would be really thankful if someone could guide me through this or try to explain for me. thanks.