can someone help me prove that cotx+tanx-1=cotx/1-tanx thank you so much!
Y yasaminG New member Joined Nov 6, 2005 Messages 27 Nov 8, 2005 #1 can someone help me prove that cotx+tanx-1=cotx/1-tanx thank you so much!
Y yasaminG New member Joined Nov 6, 2005 Messages 27 Nov 9, 2005 #2 im stuck on the last few steps, and i started with the left side.
stapel Super Moderator Staff member Joined Feb 4, 2004 Messages 16,583 Nov 9, 2005 #3 yasaminG said: im stuck on the last few steps... Click to expand... What steps have you done? Thank you. Eliz.
yasaminG said: im stuck on the last few steps... Click to expand... What steps have you done? Thank you. Eliz.
Y yasaminG New member Joined Nov 6, 2005 Messages 27 Nov 9, 2005 #4 well, im up to : (1/ (sinxcosx))-1 in not sure if thats even correct
stapel Super Moderator Staff member Joined Feb 4, 2004 Messages 16,583 Nov 9, 2005 #5 Well, since we can't see how you got there, it would be difficult to say. Please reply showing your steps. Thank you. Eliz.
Well, since we can't see how you got there, it would be difficult to say. Please reply showing your steps. Thank you. Eliz.
Y yasaminG New member Joined Nov 6, 2005 Messages 27 Nov 9, 2005 #6 ok its just hard for me to type it all out.. so here it goes: cosx/sinx {cosx} + sinx /cosx {sinx} = cos^2+sin^2x / sinxcosx -1 =1/sinxcosx -1
ok its just hard for me to type it all out.. so here it goes: cosx/sinx {cosx} + sinx /cosx {sinx} = cos^2+sin^2x / sinxcosx -1 =1/sinxcosx -1
U Unco Senior Member Joined Jul 21, 2005 Messages 1,134 Nov 9, 2005 #8 cotx+tanx-1=cotx/1-tanx Click to expand... Neither cotx+tanx-1=cotx/(1-tanx) nor cotx+tanx-1=(cotx/1) - tanx hold true as identities. Are you sure this is written correctly?
cotx+tanx-1=cotx/1-tanx Click to expand... Neither cotx+tanx-1=cotx/(1-tanx) nor cotx+tanx-1=(cotx/1) - tanx hold true as identities. Are you sure this is written correctly?
