thesheepdog
New member
- Joined
- Nov 10, 2014
- Messages
- 8
My textbook is very vague on dealing with integrals with trig and logarithms so hopefully someone on here can show me how it's done.
\(\displaystyle \int_0^{\sqrt{ln\pi}}2x e^x{^2} sin (e^x{^2}) dx\)]
A. \(\displaystyle -1\)
B.\(\displaystyle 1\)
C. \(\displaystyle 1- cos(1)\)
D. \(\displaystyle 1+cos(1)\)
\(\displaystyle \int_0^{\sqrt{ln\pi}}2x e^x{^2} sin (e^x{^2}) dx\)]
A. \(\displaystyle -1\)
B.\(\displaystyle 1\)
C. \(\displaystyle 1- cos(1)\)
D. \(\displaystyle 1+cos(1)\)
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