L LMcKendry New member Joined Nov 13, 2007 Messages 1 Nov 13, 2007 #1 I'm having problems solving this proof. Can anyone help? Prove that (cosB/1-tanB) + (sinB/1-cotB) = sinB + cosB
I'm having problems solving this proof. Can anyone help? Prove that (cosB/1-tanB) + (sinB/1-cotB) = sinB + cosB
O o_O Full Member Joined Oct 20, 2007 Messages 393 Nov 13, 2007 #2 Try starting off with converting everything on the left side into terms of sinB and cosB and combine the fractions: \(\displaystyle \L\frac{cos B}{1 - tanB} + \frac{sinB}{1-cotB}\) \(\displaystyle \L= \frac{cosB}{\frac{cosB}{cosB} - \frac{sinB}{cosB}} + \frac{sinB}{\frac{sinB}{sinB} - \frac{cosB}{sinB}}\) etc. etc.
Try starting off with converting everything on the left side into terms of sinB and cosB and combine the fractions: \(\displaystyle \L\frac{cos B}{1 - tanB} + \frac{sinB}{1-cotB}\) \(\displaystyle \L= \frac{cosB}{\frac{cosB}{cosB} - \frac{sinB}{cosB}} + \frac{sinB}{\frac{sinB}{sinB} - \frac{cosB}{sinB}}\) etc. etc.
