Scrutinize
Junior Member
- Joined
- Sep 16, 2019
- Messages
- 52
cos ( 2x ) = cos^2 ( (3x)/(2) ) Solve for x, without a specified interval.
I'm not really sure where to start, what I first did was I expanded the cos^2 ( (3x)/(2) ) into cos^2 ( (3x + 0)/(2) ) cos^2 ( (3x - 0)/(2) ) using the cos(a) + cos(b) identity I then simplified it into (cos(3x) + cos (0))/2 or (cos(3x) + 1)/2. So I had cos ( 2x) = (cos ( 3x ) + 1)/2
From there I just got lost on how to solve the question. Any help would be greatly appreciated, thanks!
I'm not really sure where to start, what I first did was I expanded the cos^2 ( (3x)/(2) ) into cos^2 ( (3x + 0)/(2) ) cos^2 ( (3x - 0)/(2) ) using the cos(a) + cos(b) identity I then simplified it into (cos(3x) + cos (0))/2 or (cos(3x) + 1)/2. So I had cos ( 2x) = (cos ( 3x ) + 1)/2
From there I just got lost on how to solve the question. Any help would be greatly appreciated, thanks!