trig word prob: find height of pole, given transit ht and

[kpx001]

to find the the geight of a pole a surveyor moves 200 feet away from the base of the pole. he uses a transit 5 feet tall which measures the angle of elevation from the top of the transit to the top of the pole to be 41 degrees. what is the height of the pole.

|\
|41\
|.......\
|..........\
|............\
|...............\
|................\
|__________\
|..................| 5
|__________|
200


this is basicly the picutre im thinking of

 

[galactus]

41 is the other angle. The way you have it, the surveyor would have to be on top of the pole. At least, that's the way I see it. Having been a surveyor, I have actually done this sort of thing.

\(\displaystyle \L\\5+200tan(41)\)

 

[skeeter]

Re: another trig word problem

to find the the geight of a pole a surveyor moves 200 feet away from the base of the pole. he uses a transit 5 feet tall which measures the angle of elevation from the top of the transit to the top of the pole to be 41 degrees. what is the height of the pole.

|\
|41\
|    \
|      \
|        \
|          \
|            \
|_____________\
|             | 5
|_____________|
     200

this is basicly the picutre im thinking of

the "41" degree angle of elevation is not at the top of the triangle as you have "pictured", it is the angle formed between the horizontal at the top of the transit to the ray that travels from the top of the transit to the top of the pole.

\(\displaystyle \L \frac{h-5}{200} = \tan(41)\)

solve for h, the height of the pole.

 

[kpx001]

which formula are u guys using?

 

[skeeter]

basic right triangle trig ...

\(\displaystyle \L \tan{\theta} = \frac{opposite \, side}{adjacent \, side}\)