I am having a difficult time solving trig inequalities. cos45 degrees is greater than cos35 degrees. True or false. i know cos 35 is larger but I don't know how to solve this kind of problem?
More than one option.
(1) Get out your calculator and enter each and compare results.
(2) Draw a sketch of each on the unit circle. Compare the lengths of the corresponding abscissas.
(3) Just do some thinking. You know the value of cos 0°. You should know the value of cos 45°. Determine how the value of the cosine function changes as it goes from 0° to 45°. Realize that cos 35° is trapped between.
If you've learned about right-triangle trigonometry, then a quick sketch and some reasoning about ratios is sufficient.
Fix the base of both triangles at 1 unit.
Do you see how the terminal side of the angle (i.e., the hypotenuse) gets longer as the angle measure increases?
The hypotenuse L is Longer, and the hypotenuse S is Shorter, but the adjacent side is the same for both.
Cosine is the ratio: Adjacent/Hypotenuse.
The ratio 1/S is larger than the ratio 1/L because a fraction with a fixed numerator GROWS as the denominator gets smaller.
However, I like Loren's unit-circle approach better because I can quickly see in my mind that the x-coordinate (i.e., the cosine) gets smaller as the angle increases in Quadrant I.
This is analagous to thinking about the shape of the graph of y = cos(x); as the angle (which is x) goes from 0 to Pi/2, the angle's cosine (which is y) goes from 1 to 0.
This site uses cookies to help personalise content, tailor your experience and to keep you logged in if you register.
By continuing to use this site, you are consenting to our use of cookies.