Ximei said:I need help solving this equation
\(\displaystyle cos5x+cos7x=sin2x\)
On the left side i got to \(\displaystyle 2cos6xcox\) , but
I don't know what to do with \(\displaystyle sin2x\)
Any help would be appreciated
Ximei said:Thank you
But after I use that
I get to \(\displaystyle cos6x=sinx\) and again I don't know what to do with \(\displaystyle sinx\)
I tried writing it like this \(\displaystyle cos6x - cos (\pi/2 - x) = 0\)
and using this
but it didn't get me anywhere
Any ideas ?