Trigonometric Equation
- Thread starter jaykee07
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Dr.Peterson
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You don't appear to have actually taken the inverse sine; you only mentioned it.
If you had evaluated [MATH]\sin^{-1}(-0.1)[/MATH], most of your work would have been appropriate.
If you had evaluated [MATH]\sin^{-1}(-0.1)[/MATH], most of your work would have been appropriate.
Dr.Peterson
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Looking again, I realize you did take the inverse sine; since you are working in radians, you got -0.10016742, which you then rounded to -0.1, so it looked as if you had not. (Your notation, with the vertical bar, is unfamiliar to me.)
On the other hand, you then made a mistake I didn't notice before (because I was only looking at the general ideas). The two possible angles are -0.10016742 and pi - (-0.10016742), which is 3.24176, not 3.04. Then you made some calculation error for the first solution, which I can't figure out. (You calculated correctly on the second, which was already wrong.)
On the other hand, you then made a mistake I didn't notice before (because I was only looking at the general ideas). The two possible angles are -0.10016742 and pi - (-0.10016742), which is 3.24176, not 3.04. Then you made some calculation error for the first solution, which I can't figure out. (You calculated correctly on the second, which was already wrong.)
topsquark
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I must say it's rather refreshing to see an image posted that is readable. Thank you!
-Dan