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trigonometric equation
- Thread starter giuly
- Start date
\(\displaystyle \text{ You have to show work -- Similar equations where given before and were solved }\)
\(\displaystyle sinx+\sqrt2=-sinx\)
\(\displaystyle sinx+sinx=-\sqrt2\)
\(\displaystyle (sinx)(1+1)=-\sqrt2\)
\(\displaystyle sinx=-\frac{\sqrt2}{2}\)
So , x =
\(\displaystyle sinx+\sqrt2=-sinx\)
\(\displaystyle sinx+sinx=-\sqrt2\)
\(\displaystyle (sinx)(1+1)=-\sqrt2\)
\(\displaystyle sinx=-\frac{\sqrt2}{2}\)
So , x =
BigGlenntheHeavy
Senior Member
- Joined
- Mar 8, 2009
- Messages
- 1,577
\(\displaystyle sin(x)+\sqrt 2 \ = \ -sin(x)\)
\(\displaystyle 2sin(x) \ = \ -\sqrt 2\)
\(\displaystyle sin(x) \ = \ \frac{-\sqrt 2}{2}\)
\(\displaystyle x \ = \ arcsin(\frac{-\sqrt 2}{2}) \ = \ \frac{-\pi}{4}\)
\(\displaystyle 2sin(x) \ = \ -\sqrt 2\)
\(\displaystyle sin(x) \ = \ \frac{-\sqrt 2}{2}\)
\(\displaystyle x \ = \ arcsin(\frac{-\sqrt 2}{2}) \ = \ \frac{-\pi}{4}\)