Trigonometric equations

Kcashew

New member
Joined
Mar 17, 2020
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18
Just to clarify, my equation goes like this:

(e^t)dt/((36+e^t)^0.5)

The answer I have given in this picture is incorrect.

I feel that I may not have factored out the one-sixths correctly, but I wanted to see if there was some other problem with my arithmetic.

Is there anywhere else that I messed up?
 

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topsquark

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Aug 27, 2012
Messages
920
Yes, you need to cancel both 6s on the first line. You also apparently did a substitution and didn't change the limits on your integral. Since you didn't apply those limits until you back-substituted it worked out okay but it's a bad habit and a potential cause for confusion. Other than that, after you fix the 6 problem and carry it through it looks okay.

-Dan
 

Subhotosh Khan

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Staff member
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Jun 18, 2007
Messages
20,986
Just to clarify, my equation goes like this:

(e^t)dt/((36+e^t)^0.5)

The answer I have given in this picture is incorrect.

I feel that I may not have factored out the one-sixths correctly, but I wanted to see if there was some other problem with my arithmetic.

Is there anywhere else that I messed up?
If you substitute:

x = (e^t/6), you would get:

Int = sinh-1(et/6) + C
 
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