Given that sin 50 degrees = p, express sin 230 degrees and cos 50 degrees in terms of p.
I IloveManUtd New member Joined Jul 27, 2010 Messages 48 Aug 3, 2010 #1 Given that sin 50 degrees = p, express sin 230 degrees and cos 50 degrees in terms of p.
mmm4444bot Super Moderator Joined Oct 6, 2005 Messages 10,902 Aug 3, 2010 #2 Here are two identities for you to consider (angles in degrees). sin(x + 180) = -sin(x) cos(x) = ±sqrt[1 - sin^2(x)]
Here are two identities for you to consider (angles in degrees). sin(x + 180) = -sin(x) cos(x) = ±sqrt[1 - sin^2(x)]