H Helen Junior Member Joined Oct 28, 2007 Messages 106 Nov 8, 2007 #1 If x^c and x^e are denominators of two fractions and c>e, then x^c is the LCD. I say that it is false, but not completely sure. Can you please help?
If x^c and x^e are denominators of two fractions and c>e, then x^c is the LCD. I say that it is false, but not completely sure. Can you please help?
skeeter Elite Member Joined Dec 15, 2005 Messages 3,204 Nov 8, 2007 #2 what is the LCD of the two fractions \(\displaystyle \L \frac{a}{x^3}\) and \(\displaystyle \L \frac{b}{x^2}\) ?
what is the LCD of the two fractions \(\displaystyle \L \frac{a}{x^3}\) and \(\displaystyle \L \frac{b}{x^2}\) ?
H Helen Junior Member Joined Oct 28, 2007 Messages 106 Nov 8, 2007 #3 Intermediate Algebra Skeeter, You asked what the LCD was for the two fractions: a ----- x^3 and b ---- x^2 I think that it is 6. Is that correct? Thank you for your help!
Intermediate Algebra Skeeter, You asked what the LCD was for the two fractions: a ----- x^3 and b ---- x^2 I think that it is 6. Is that correct? Thank you for your help!
skeeter Elite Member Joined Dec 15, 2005 Messages 3,204 Nov 9, 2007 #4 no ... do you know what LCD means?
H Helen Junior Member Joined Oct 28, 2007 Messages 106 Nov 9, 2007 #5 Algebra Skeeter, LCD means Least Common Denominator. 2 and 3 both go into 6. What am I doing wrong? Thank you.
Algebra Skeeter, LCD means Least Common Denominator. 2 and 3 both go into 6. What am I doing wrong? Thank you.
pka Elite Member Joined Jan 29, 2005 Messages 11,978 Nov 9, 2007 #6 Re: Algebra Helen said: Skeeter, LCD means Least Common Denominator. 2 and 3 both go into 6. What am I doing wrong? Click to expand... Because \(\displaystyle \L \frac{{x^3 }}{{x^2 }} = x\) then \(\displaystyle \L x^3\) is the LCD.
Re: Algebra Helen said: Skeeter, LCD means Least Common Denominator. 2 and 3 both go into 6. What am I doing wrong? Click to expand... Because \(\displaystyle \L \frac{{x^3 }}{{x^2 }} = x\) then \(\displaystyle \L x^3\) is the LCD.
H Helen Junior Member Joined Oct 28, 2007 Messages 106 Nov 14, 2007 #7 Intermediate Algebra pka, Just a late thank you! Helen
