Hi all. So I'm tutoring a student on another forum and I've found a problem that's given me some grief. I think there might be an error in the problem somewhere, and I just want to make sure I'm not going crazy or missing something obvious. The full text of the problem is:
By the sum and constant multiple rules, it's trivial to get it down to:
\(\displaystyle 3(4) + 2(2) + \int 1 \: dx\)
But wouldn't this necessarily have to produce an answer of 16 + x + C? The given answer choices were:
97. If \(\displaystyle \int f(x) \: dx = 4\) and \(\displaystyle \int g(x) \: dx = 2\), find \(\displaystyle \int \left[ 3f(x) + 2g(x) + 1 \right] \: dx\)
By the sum and constant multiple rules, it's trivial to get it down to:
\(\displaystyle 3(4) + 2(2) + \int 1 \: dx\)
But wouldn't this necessarily have to produce an answer of 16 + x + C? The given answer choices were:
- A: 23
- B: 22
- C: 25
- D: 24