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- Thread starter hajfajv
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- Nov 19, 2021

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That gives me x(x-4)=-3 but that doesn't help isolate x?

The quadratic formula

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No, it does not. Have you looked up "Quadratic equation" on internet?That gives me x(x-4)=-3 but that doesn't help isolate x?

But I thought I was supposed to isolate x or y in one equation then input that result into another and then oh## What do you feed a baby parabola?

Quadratic formula

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You did the right thing to reduce the system of two equations with two variables to a single equation with a single variable.But I thought I was supposed to isolate x or y in one equation then input that result into another and then oh

Now you need to solve the resulting quadratic equation.

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Are you sure that 2/2 = 4? Maybe that's your 1, just look like a 4.

You could've also done it through the method of grouping.

[math]x^2-4x+3=0\\ (x^2-x)+(-3x+3)=0\\ x(x-1)-3(x-1)=0\\ (x-1)(x-3)=0 \implies x=1, x=3[/math]

You could've also done it through the method of grouping.

[math]x^2-4x+3=0\\ (x^2-x)+(-3x+3)=0\\ x(x-1)-3(x-1)=0\\ (x-1)(x-3)=0 \implies x=1, x=3[/math]

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Oh yea my 1's 4's and 9's are not reading friendly

I'm terrible at factorizing quadratics and therefore tend to avoid it, so I need to work on that aspect.

I cannot remeber is seeing your grouping method, will look into that seems like a time saver.

In your work, when you use the Quadratic Formula, you should be showing a, b, c being substituted correctly,

preferably each of them inside parentheses.

Also, x = 3

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If you are familiar quadratic equations, may I ask why you are having difficulties with the problem?

Oh yea my 1's 4's and 9's are not reading friendly

I'm terrible at factorizing quadratics and therefore tend to avoid it, so I need to work on that aspect.

I cannot remeber is seeing your grouping method, will look into that seems like a time saver.