Two Quick Questions

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Jan 25, 2006
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Hello everyone, I have a two quick questions about a study guide.

#1

It says use descartes rule of signs to determine the possible number of negative real zeros for the function.

-2x^4 - 2x^3 - 6x^2 - 3x + 2 = 0

the answer is (3, 1) negatives. I understand where the 3 came from but where does the 1 possible negative zero come from. I thought it should be 3 or 0 negative zeros.

#2

Use the boundedness theorem to determine whether the statement is true or false.
The polynomial f(x)=x^4 - x^3 + 2x^2 - 4x - 10 has no real zero greator than 3.

*I've been looking at the bound theorem in my book and I still do not understand how one is suppose to determine this. This answer is TRUE. Can someone please clue me in on how to do this.

- Thanks.
 
1) You have not told us what we are looking at. Is it f(x) or f(-x)? Anyway, if a polynomial has Real coefficients, Complex roots must come in complex conjugate pairs. 3 or 0 just isn't possible. 3 or 1 is.

2) It may appear as "Least Upper Bound" or something like that. The easiest description refers to the bottom line in a synthetic division tableau. If everything is positive, it's only going to get worse. Whatever you used is AN upper bound.
 
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