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- Thread starter aname
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Deleted member 4993
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I have a question regarding the antiderivative of this function
\(\displaystyle f(x)\, =\, \dfrac{1}{3\, \cos^2 (2x)}\)
the u is cos(2x), right? what do I do after that? If I take du, I end up with -2sin(2x)....
No...
u = 2x
\(\displaystyle \dfrac{1}{cos^2(u)} = sec^2(u)\)
Now continue....
Last edited by a moderator:
I have a question regarding the antiderivative of this function
\(\displaystyle f(x)\, =\, \dfrac{1}{3\, \cos^2 (2x)}\)
the u is cos(2x), right? what do I do after that? If I take du, I end up with -2sin(2x)....
What is the derivative of tan(x)?
Last edited by a moderator: