#### Ted_Grendy

##### New member

- Joined
- Nov 11, 2018

- Messages
- 26

I was wondering if someone could clear up some doubt in my mind.

I am trying to get my head around the Binomial Theorem.

The Binomial Theorem states:-

(a+b)^n = a^n +na^n-1b + n(n-1)/2! * a^n-2*b^2 + n(n-1)(n-2)/3! * a^n-3*b^3 + ...

The problem is that I have been given a Binomial Theorem which is different to the above, it states:-

(1+b)^n = 1 + nb + n(n-1) * b^2/2! + n(n-1)(n-2)b^3/3! + ....

Are they the same where does the 1 come from in the (1+b) side? shouldn't it be a ???

Can someone help?

Thank you.