tristatefabricatorsinc
Junior Member
- Joined
- Jan 31, 2006
- Messages
- 60
Two mountain bikers started from the ranger station in the Cascade Mountains traveling in the same direction on the same road. The first biker left 1 hour earlier than the second and traveled 10 mph. The second biker left later and traveled 15 mph. By 4:00 p.m., the second biker had passed the first and was 5 miles ahead of the first biker. What time did the first biker leave the ranger station?
Heres my work...
Velocity Time Distance
First Biker 10 t-1
Second Biker 15 t +5
Equation I came up with...
15t + 5 = 10(t-1)
15t + 5 = 10t - 10
5 = -5t - 10
15 = -5t
t = -3
so the first biker would have left at 1:00 p.m. (4 - 3 = 1)
Does this sound correct or did I set up the formula improperly. If so, can someone tell me where I messed up?
Thank You!
Heres my work...
Velocity Time Distance
First Biker 10 t-1
Second Biker 15 t +5
Equation I came up with...
15t + 5 = 10(t-1)
15t + 5 = 10t - 10
5 = -5t - 10
15 = -5t
t = -3
so the first biker would have left at 1:00 p.m. (4 - 3 = 1)
Does this sound correct or did I set up the formula improperly. If so, can someone tell me where I messed up?
Thank You!