Unsure of how to start problem
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mmm4444bot
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If both dice are rolled at the same time, then there's no need to consider absolute value. If the two numbers are different, then subtract the smaller number from the larger number. Have you posted the complete exercise statement, as given?
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[imath]\;[/imath]
Harry_the_cat
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Start off by completing the table below with the absolute difference of the two dice. I've filled in a few cells for you.
1 | 2 | 3 | 4 | 5 | 6 | |
1 | 0 | 4 | ||||
2 | ||||||
3 | ||||||
4 | | |||||
5 | 3 | |||||
6 | 2 |
topsquark
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Okay. But what is the problem you are working on that you need help with? Making the actual table?
-Dan
pka
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Here is a basic outcome table of tossing two standard dice.
[imath](1,1) (1 ,2) (1 ,3) (1 ,4) (1 ,5) (1 ,6)\\(2,1) (2 ,2) (2 ,3) ( 2,4) (2 ,5) (2 ,6)\\(3,1) (3 ,2) (3 ,3) (3 ,4) (3 ,5) (3 ,6)\\(4,1) ( 4,2) (4 ,3) (4 ,4) (4 ,5) (4 ,6)\\ (5,1) (5 ,2) (5 ,3) (5 ,4) (5 ,5) (5 ,6)\\(6,1) (6 ,2) (6 ,3) (6 ,4) (6 ,5) (6 ,6)[/imath]
Note that if [imath]N=|X-Y|[/imath] then [imath]N=0, 1, 2, 3, 4, 5[/imath]
Moreover [imath]\mathcal{P}(N=0)=\dfrac{6}{36}[/imath] but whereas [imath]\mathcal{P}(N=5)=\dfrac{2}{36}[/imath]
You need to workout the probabilities for [imath]N=1,2,3,4[/imath] making sure that all six add to one.