How I can argue that the upper limit and the lower limit of this sequence are \frac{2}{3} (a_2n) and \frac{-2}{3}(a_{2n+1})? (with all the steps please)
a_n=\frac{1+2n(-1)^n}{1+3n}
How I can argue that the upper limit and the lower limit of this sequence are [MATH]\frac{2}{3} a_{2n} [/MATH]and [MATH]\frac{-2}{3}a_{2n+1}[/MATH])? (with all the steps please)
[MATH]a_n=\frac{1+2n(-1)^n}{1+3n}[/MATH]
PS: I don´t know how to activate Latex code
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