I have got the first part done ( in the paraenthesis) but I don't get the square root of a fraction! What are the steps(if you could show me on an example with out adding the actual(SP?) problem it would be greatly appreaciated.

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I have got the first part done ( in the paraenthesis) but I don't get the square root of a fraction! What are the steps(if you could show me on an example with out adding the actual(SP?) problem it would be greatly appreaciated.

J

Like tkhunny, I am unsure of what your question is.

However, there is nothing mysterious anout the square root of a fraction. Provided a is a non-negative real number, its square root is defined as the non-negative number b such b * b = a. The definition does not care about fractions or whole numbers.

So the square root of (4/9) is (2/3) because (2/3) * (2/3) = (4/9).

It may help to realize that the square root of (c / d) = (the square root of c) / (the square root of d).

The 1/2 of the square root of 6 I have figured out. The transforming of the second fraction confuses me.tkhunny said:\(\displaystyle \frac{1}{2}\cdot\sqrt{6}-\sqrt{\frac{3}{2}}\)

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Hint: \(\displaystyle \sqrt{\frac{3}{2}} = \sqrt{\frac{3\cdot 2}{2\cdot 2}}\)

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Find the square root.

Calculate the square root.

Determine the square root.

Various ways to say it.

You must utilize this principle, a/a = 1 for a <> 0 until you get those radical s out fo the denominator. Personally, I do not recommend such practices, but if you have to pass a test with it, then learn it.