studentCal
New member
- Joined
- Sep 30, 2011
- Messages
- 6
Note that \(\displaystyle |2x^2-4x-6|=2|x+1||x-3|\).
Start by stipulating that \(\displaystyle 0<\delta<1\).
If \(\displaystyle |x-3|<1\) then \(\displaystyle |x+1|<~?\)im abit confused, where did you get 5 from?