Hi everyone!
How do I determine the minimum value of y = x^2 + 16/x using the mean inequality?
x is greater than 0. I'm not supposed to do this graphically/with a graphing calculator.
the mean inequality is: (a+b)/2 is greater or equal to sqrt(ab)
I think the first step would be to use x and y as the (a, b) values.
And since x and y aren't equal, it would be:
(x+y)/2 > sqrt(xy)
But I'm not sure how to continue/what to do next.
Any help is greatly appreciated!
How do I determine the minimum value of y = x^2 + 16/x using the mean inequality?
x is greater than 0. I'm not supposed to do this graphically/with a graphing calculator.
the mean inequality is: (a+b)/2 is greater or equal to sqrt(ab)
I think the first step would be to use x and y as the (a, b) values.
And since x and y aren't equal, it would be:
(x+y)/2 > sqrt(xy)
But I'm not sure how to continue/what to do next.
Any help is greatly appreciated!