f(x)= ax+b

2a^2+ 6b^2 =3

x belongs to: [-1, 1]

Prove: |f(x)| is less than or equal to sqrt(2)

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f(x)= ax+b

2a^2+ 6b^2 =3

x belongs to: [-1, 1]

Prove: |f(x)| is less than or equal to sqrt(2)

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- Jan 27, 2012

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- 4,878

Am I right in saying that the maximum possible value is sqrt(2) / 2 and minimum is - sqrt(2) / 2 ?

- Joined
- Jan 27, 2012

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Well, how did you get that answer?