Hey everyone! Here's a question which states that I have to solve it with trigonometry. I had the idea of substituting x as sine or cosine, because of the range but I don't know which would be more suitable. I'm supposed to substitute trigonometric identities (like sin α or something and have a range for α) to do the question. Please help asap!
f(x)= ax+b
2a^2+ 6b^2 =3
x belongs to: [-1, 1]
Prove: |f(x)| is less than or equal to sqrt(2)
f(x)= ax+b
2a^2+ 6b^2 =3
x belongs to: [-1, 1]
Prove: |f(x)| is less than or equal to sqrt(2)