KindofSlow
Junior Member
- Joined
- Mar 5, 2010
- Messages
- 90
Problem: Air resistance on falling body is a = dv/dt = g-kv with k is constant. Find v(t) assuming starts from rest.
Here's my work.
dv/dt = g-kv
dv = (g-kv)dt
1/(g-kv)dv = dt
∫ 1/(g-kv)dv = ∫dt
u = (g-kv) , du/dv = -k , -1/k du = dv
-1/k ∫ 1/u du = ∫ dt
(-1/k)(ln(g-kv)) = t
ln(g-kv) = -kt
g-kv = e^(-kt)
kv = g - e^(-kt)
v = 1/k(g-e^(-kt))
Correct answer according to book is v = g/k(1-e^(-kt))
I feel like I've gotten close but I must have a mistake somewhere and I cannot find it.
If anyone can point out my error, I would appreciated it.
Thank you
Here's my work.
dv/dt = g-kv
dv = (g-kv)dt
1/(g-kv)dv = dt
∫ 1/(g-kv)dv = ∫dt
u = (g-kv) , du/dv = -k , -1/k du = dv
-1/k ∫ 1/u du = ∫ dt
(-1/k)(ln(g-kv)) = t
ln(g-kv) = -kt
g-kv = e^(-kt)
kv = g - e^(-kt)
v = 1/k(g-e^(-kt))
Correct answer according to book is v = g/k(1-e^(-kt))
I feel like I've gotten close but I must have a mistake somewhere and I cannot find it.
If anyone can point out my error, I would appreciated it.
Thank you