(k-1)(k-2)(k+3)(k-4)x = (k-3)(k-4)(k-5)(k-6)

For which value(s) of k will the system have 1) no solution 2) exactly one solution 3) infinite many solutions

I tried and my answer is 1) k= 1,2,-3 , 2) k unequals to 1,2,-3,4 and 3) k=4

Can anyone please correct me.