Y YOU NO DARK SKIN New member Joined Mar 3, 2015 Messages 5 Mar 3, 2015 #1 Let u = (5, 3, -4) and v = (4, 0, 1). Find the vector w = 4u - 5v and it's additive inverse. w = (_, _, _), -w = (_, _, _).
Let u = (5, 3, -4) and v = (4, 0, 1). Find the vector w = 4u - 5v and it's additive inverse. w = (_, _, _), -w = (_, _, _).
S Some1 New member Joined Jan 30, 2015 Messages 16 Mar 3, 2015 #2 First question: w = 4u - 5v 4u = (4 * 5, 4 * 3, 4 *-4) = (20, 12, -26) 5v = (5 * 4, 5 * 0, 5 * 1) = (20, 0, 5) therefore: w = (20 - 20, 12 - 0, -26 - 5) = (0, 12, -31) Second question: The additive inverse is a fancy way of saying "times it by -1" adding a value and its additive inverse gives you 0. so -w = (0, -12, 31) Hope this helped!
First question: w = 4u - 5v 4u = (4 * 5, 4 * 3, 4 *-4) = (20, 12, -26) 5v = (5 * 4, 5 * 0, 5 * 1) = (20, 0, 5) therefore: w = (20 - 20, 12 - 0, -26 - 5) = (0, 12, -31) Second question: The additive inverse is a fancy way of saying "times it by -1" adding a value and its additive inverse gives you 0. so -w = (0, -12, 31) Hope this helped!