T Timcago Junior Member Joined Apr 13, 2006 Messages 77 Jul 14, 2006 #1 sin(x + y + z) = sin(x)cos(y)cos(z) + cos(x)sin(y)cos(z) + cos(x)cos(y)sin(z) - sin(x)sin(y)sin(z) This is insane! :shock: I dont even know which side i should try to turn into the other. Please help.
sin(x + y + z) = sin(x)cos(y)cos(z) + cos(x)sin(y)cos(z) + cos(x)cos(y)sin(z) - sin(x)sin(y)sin(z) This is insane! :shock: I dont even know which side i should try to turn into the other. Please help.
pka Elite Member Joined Jan 29, 2005 Messages 11,978 Jul 14, 2006 #2 sin(x+y+z)=sin(x+y)cos(z)+cos(x+y)sin(z)=[sin(x)cos(y)+cos(x)sin(y)]cos(z)+cos(x+y)sin(z). Now you finish it.
sin(x+y+z)=sin(x+y)cos(z)+cos(x+y)sin(z)=[sin(x)cos(y)+cos(x)sin(y)]cos(z)+cos(x+y)sin(z). Now you finish it.
