Volume of Solid

[Jason76]

Shouldn't the area formula be \(\displaystyle A = \dfrac{1}{2}bh\) ?

Here it is only \(\displaystyle A= bh\)

How would this differ from this problem, where \(\displaystyle A= \dfrac{1}{2} bh\)

 

[daon2]

View attachment 3689

Shouldn't the area formula be \(\displaystyle A = \dfrac{1}{2}bh\) ?

Here it is only \(\displaystyle A= bh\)

How would this differ from this problem, where \(\displaystyle A= \dfrac{1}{2} bh\)

View attachment 3690

The area of a rectangle is not 1/2(b)(h)...

 

[Jason76]

Right, I realized that a little later. Two different shapes.