Does this look right?
M mistiksky New member Joined Jul 26, 2012 Messages 3 Jul 26, 2012 #1 Does this look right? Last edited by a moderator: Jul 26, 2012
tkhunny Moderator Staff member Joined Apr 12, 2005 Messages 11,339 Jul 26, 2012 #2 You have demonstrated only the ability to copy an answer. What substitution did you use?
mmm4444bot Super Moderator Joined Oct 6, 2005 Messages 10,962 Jul 26, 2012 #3 I do not see any work, but the answer looks correct. By the way, your parentheses around the sine output are unnecessary.
I do not see any work, but the answer looks correct. By the way, your parentheses around the sine output are unnecessary.
G galactus Super Moderator Staff member Joined Sep 28, 2005 Messages 7,216 Jul 27, 2012 #4 Often with substitution, look at what is in parentheses. Use that for the sub. In this case, try letting u=x9+9, du9=x8dx\displaystyle u=x^{9}+9, \;\ \frac{du}{9}=x^{8}dxu=x9+9, 9du=x8dx This is certainly not always the case, but with this one it looks promising. After making this sub, there is one more obvious sub you can make and you have it. Last edited: Jul 27, 2012
Often with substitution, look at what is in parentheses. Use that for the sub. In this case, try letting u=x9+9, du9=x8dx\displaystyle u=x^{9}+9, \;\ \frac{du}{9}=x^{8}dxu=x9+9, 9du=x8dx This is certainly not always the case, but with this one it looks promising. After making this sub, there is one more obvious sub you can make and you have it.