What are the chances the Empress and Hanged Man will show up in position 8 AND 9?

[Tarot reader]

I was reading the Tarot Cards for my new beau. There are 72 cards in the deck, but we removed his "Signifier" card that represents him. Therefore, we are drawing from 71 cards to read his fortune. It just so happens that I am represented by the Empress and the Hanged Man cards.
The Celtic Cross is a common layout for reading Tarot Cards, consisting of 9 cards drawn and placed on the table in a particular (unimportant to this math question) arrangement. What are the chances that the Hanged Man will be in position #8 and the Empress will be in position #9? Oh, and also each card could be right-side-up or upside-down. The reading is completely different if they are reversed, so calculate the probability of them being right-side-up. Keep in mind, this actually happened in real life (see photo). Kinda spooky, huh?

 

[HallsofIvy]

You are drawing from any one of 71 cards so the probability any specific one, such as the "empress", is in position 8 is 1/71. Give that there are 70 cards left so the probability another. such as the "hanged man", is in position 9 is 1/70. The probability the "empress" is in position 8 and the "hanged man" is in position 9 is (1/71)(1/70). Since "right-side up" or "upside-down" are the 2 possible position, the probabilty of either card being a specific one or those Is 1/2 the previous probability. That is the probabilities of "empress in position 8, hanged man in position 9" and both right side up or both upside down, or empress right side up and hanged man upside down, or empress upside down and hanged man right side up are each (1/2)(1/2)(1/71)(1/70),

 

[Tarot reader]

Does your answer take into account the position of the card on the table? Because each time you lay out a card, the number of cards in the deck is reduced. And you have to make sure that the first seven cards lain on the table are NOT the two cards that end up in position #8 and position #9...