What does f(u)(t-u) mean in this convolution equation?

Sofia12345

New member
I don't understand what f(u)(t-u) means in the following maths problem. Is it somehow a function of a function or a function multiplied by (t-u)? Or something else? The question is:

Please solve the following convolution equation:

∫ f(u)(t-u) cos(2(t-u)) du = ∫ sin(2u) sin(2(t-u)) du

(Both integrals go from 0 to t)

Last edited:

Dr.Peterson

Elite Member
I don't understand what f(u)(t-u) means in the following maths problem. Is it somehow a function of a function or a function multiplied by (t-u)? Or something else? The question is:

Please solve the following convolution equation:

∫ f(u)(t-u) cos(2(t-u)) du = ∫ sin(2u) sin(2(t-u)) du

(Both integrals go from 0 to t)
There is no strange notation being used here; it just means f(u) times (t-u), as one would expect.